Respuesta :

Cowmilk

[tex] log_{3}(9) + log_{3}(27) \\ = 2 + 3 = 5 \\ \\ log_{2}(8) + log_{2}(16) \\ = 3 + 4 = 7 \\ \\ log_{10}(80) + log_{10}(125) \\ = log_{10}(80 \times 125) \\ = log_{10}(10000) \\ = 4[/tex]