Respuesta :

LammettHash
[tex]\dbinom{2n}2=\dfrac{(2n!)}{2!(2n-2)!}=\dfrac{2n(2n-1)}2=n(2n-1)=2n^2-n[/tex]

[tex]2\dbinom n2+n^2=2\dfrac{n!}{2!(n-2)!}+n^2=n(n-1)+n^2=2n^2-n[/tex]

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