[tex]\huge{\boxed{66}}[/tex]
Start by substituting in the values. [tex]3(2)+6(8+2)[/tex]
Add. [tex]3(2)+6(10)[/tex]
Multiply. [tex]6+60[/tex]
Add. [tex]\boxed{66}[/tex]
Answer:
Step-by-step explanation:
3a+6(b+2)
=3(2)+6(8+2)
=6+6(10)
=6+60
=66
