3x over 4x subtract 12 subtract 9 over 4x subtract12
[tex] \frac{3x}{4x - 12 -} - \frac{9}{4x - 12} [/tex]

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person150752 person150752 · Answer 1 · 2019-02-23T20:47:15+01:00

Answer:

[tex]\frac{3}{4}[/tex]

Step-by-step explanation:

Both fractions have a common denominator, so you can subtract the numerators with the same denominator at the bottom:

[tex]\frac{3x-9}{4x-12}[/tex]

Then you can factor:

[tex]\frac{3(x-3)}{4(x-3)}[/tex]

Both (x-3)s will cancel out, leaving

[tex]\frac {3}{4}[/tex]

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tramserran tramserran · Answer 2 · 2019-02-23T21:53:55+01:00

Answer: [tex]\bold{x=\dfrac{3}{4}}[/tex]

Step-by-step explanation:

[tex]\dfrac{3x}{4x-12}-\dfrac{9}{4x-12}\\\\\\= \dfrac{3x-9}{4x-12}\\\\\\=\dfrac{3(x-3)}{4(x-3)}\\\\\\=\dfrac{3}{4}[/tex]

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