Answer: [tex]3.33J/g^oC[/tex]
Explanation:
[tex]Q= m\times c\times \Delta T[/tex]
Q= heat gained = 550 J
m = mass of the substance = 6.0 g
c = heat capacity of iron = ?
[tex]\Delta T={\text{Change in temperature}}=(45-20)^oC=25^0C[/tex]
[tex]500J=6.0g\times c\times 25^oC[/tex]
[tex]c= 3.33J/g^oC[/tex]
Thus specific heat of the glass sample is [tex]3.33J/g^oC[/tex]
