LT23
LT23 LT23
  • 06-06-2018
  • Mathematics
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The function h is defined by h(x)=4+4x/5+x . Find h(x+2).

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  • 06-06-2018
[tex]h(x)=\dfrac{4+4x}{5+x}\\\\\text{substitute x+2}\\\\h(x+2)=\dfrac{4+4(x+2)}{5+(x+2)}=\dfrac{4+4x+8}{5+x+2}=\dfrac{4x+12}{x+7}[/tex]
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